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HCL | 18 Sept'10 | JAVA/J2EE

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( 1 Vote )
HCL Technologies (www.hcltech.com)

Experienced Walk-In : Java /J2EE Professionals
Job Position : Senior Software Engineer

Job Location : Chennai, Tamilnadu

Desired Experience : 3 to 7 Years (Mandatory)

Job Description :
We have requirements across projects in Banking & Financial Domain in Chennai.
- Experience in Core Java / Swing or J2EE / Spring / Hibernate, Struts, EJB, Ajax, Weblogic, RMI, JSP, JDBC (All skills are not mandatory)
- Knowledge in BFSI Domain is preferred
- Excellent analytical and problem solving approach
- Very good communication skills (Written & Oral)

Walk-In Date : On 18th September 2010 (Saturday) | 10 AM - 1 PM
Venue :
HCL Technologies Ltd;
Aurora Building,
34&35, Haddows Road,
Nungambakkam,
Chennai 600 034
Contact Person : Narmada, Jude

Mahindra Satyam

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( 18 Votes )

There is a square with each of it’s side is of 2m. An octagonal is cut-of from this square by cutting it’s edge such that the octagonal has all it’s sides equal. Find out the length of each side of the octagonal?
Ans: 2/(1+(2)1/2 )

 

Which one is wrong in the following series?

3 7 4 10 6 8 5
Ans: 8

 

A lorry starts from Banglore to Mysore at 6.00 A.M,7.00am , 8.00am ....... 10 pm. Similarly one another starts from Mysore to Banglore at 6.00 , 7.00 am, 8.00 am.....10.00pm. A lorry takes 9 hours to travel from Banglore to Mysore and vice versa. 
(i) A lorry which has started at 6.00 am will cross how many lorries. 
ans. 10 
(ii)A lorry which had started at 6.00pm will cross how many lorries. 
ans. 14

 

In a school, no of students who passed are three times the number of students who failed. If the no of students would have been decreased by 16 and the no of students who failed would be increased by 6, then the no of students who would have passed are 80. Then find out the no of students in the school?
Ans: 136

 

1,000,000 seconds are equal to________days?
Ans: 11.57days

 

A Japanese and an American were traveling together in a flight. The American asked to Japanese why Japanese look are inscrutable. Japanese replied that the people of Japan are inscrutable not have the aim of only focusing on money etc. Which of the following term describe their behaviour?
1. Indifferent
2. Compassionate
3. Emotional
4. None of these

 

The probability of withdrawing a card of ace is 1 in 52. Find the probability that we obtain one card of king, (3 things r given)…sorry I don’t remember.

  1. There is one question from Compound Interest.
  2. A man has to drive for 12 miles to reach his office. The office of his wife is 6 miles from his office. After picking his wife in the evening, he went to gym that is 4miles away. If he is x miles away from his home right now, then the range of x is:
    a. 4<=x<=22
    b. 2<=x<=22
    c. 3<=x<=24
    d. none
    Ans: b


There are 10000 families, having 4 children for each family. what is the probability that there will be 2 daughters for each house.
a)625
b)529
e)none of these 


If 27th december 1928 is monday then what is the day of 27th december 2004?
ans: i think it was thursday. 

If a monkey climbs  3 steps and comes down 2 steps in an hour....den how much time will it take 4 him to climb 20 steps?
a)10hr
b)12hr
c)18hr
d)20hr
answr-c (18hr)


A certain article cost something and a second article cost 20%less than the 1st ariticle.if a person gain (25/2)% on d 1st article and loses 10% on d second article,den find d overall gain or loss on d whole transaction?
a)25/2% gain
b)25/2% loss


One question was in the form as listed below but it is not the exact one:  there was a series given like 12, 23, 34, 56, 178,342
step 1)24,47,57,234,435
step2)
step3)
like this they have given  5 steps and they have given a new series for which we have to find the relatin between the given series and step 5.
ans: it was little bit tough, but most of the times its answer is none of these.


Accenture

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( 1 Vote )
Accenture is a global management consulting, technology services and outsourcing company. Combining unparalleled experience, comprehensive capabilities across all industries and business functions, and extensive research on the world’s most successful companies, Accenture collaborates with clients to help them become high-performance businesses and governments. With with more than 181,000 people serving clients in more than 120 countries, the company generated net revenues of US$21.58 billion for the fiscal year ended Aug. 31, 2009.
a
Their "high performance business" strategy builds on the expertise in consulting, technology and outsourcing to help clients perform at the highest levels so they can create sustainable value for their customers and shareholders. Using their industry knowledge, service-offering expertise and technology capabilities, they identify new business and technology trends and develop solutions to help clients around the world.
a
Accenture has extensive relationships with the world's leading companies and governments and work with organizations of all sizes—including 96 of the Fortune Global 100 and more than three quarters of the Fortune Global 500.

Memory Management

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( 0 Votes )
Memory Management
1. What is the difference between Swapping and Paging?
Swapping:
Whole process is moved from the swap device to the main memory for execution. Process size must be less than or equal to the available main memory. It is easier to implementation and overhead to the system. Swapping systems does not handle the memory more flexibly as compared to the paging systems.
Paging:
Only the required memory pages are moved to main memory from the swap device for execution. Process size does not matter. Gives the concept of the virtual memory.
It provides greater flexibility in mapping the virtual address space into the physical memory of the machine. Allows more number of processes to fit in the main memory simultaneously. Allows the greater process size than the available physical memory. Demand paging systems handle the memory more flexibly.
2. What is major difference between the Historic Unix and the new BSD release of Unix System V in terms of Memory Management?
Historic Unix uses Swapping – entire process is transferred to the main memory from the swap device, whereas the Unix System V uses Demand Paging – only the part of the process is moved to the main memory. Historic Unix uses one Swap Device and Unix System V allow multiple Swap Devices.
3. What is the main goal of the Memory Management?
 It decides which process should reside in the main memory,
 Manages the parts of the virtual address space of a process which is non-core resident,
 Monitors the available main memory and periodically write the processes into the swap device to provide more processes fit in the main memory simultaneously.
4. What is a Map?
A Map is an Array, which contains the addresses of the free space in the swap device that are allocatable resources, and the number of the resource units available there.
This allows First-Fit allocation of contiguous blocks of a resource. Initially the Map contains one entry – address (block offset from the starting of the swap area) and the total number of resources.
Kernel treats each unit of Map as a group of disk blocks. On the allocation and freeing of the resources Kernel updates the Map for accurate information.
5. What scheme does the Kernel in Unix System V follow while choosing a swap device among the multiple swap devices?
Kernel follows Round Robin scheme choosing a swap device among the multiple swap devices in Unix System V.
6. What is a Region?
A Region is a continuous area of a process’s address space (such as text, data and stack). The kernel in a ‘Region Table’ that is local to the process maintains region. Regions are sharable among the process.
7. What are the events done by the Kernel after a process is being swapped out from the main memory?
When Kernel swaps the process out of the primary memory, it performs the following:
 Kernel decrements the Reference Count of each region of the process. If the reference count becomes zero, swaps the region out of the main memory,
 Kernel allocates the space for the swapping process in the swap device,
 Kernel locks the other swapping process while the current swapping operation is going on,
 The Kernel saves the swap address of the region in the region table.
8. Is the Process before and after the swap are the same? Give reason.
Process before swapping is residing in the primary memory in its original form. The regions (text, data and stack) may not be occupied fully by the process, there may be few empty slots in any of the regions and while swapping Kernel do not bother about the empty slots while swapping the process out.
After swapping the process resides in the swap (secondary memory) device. The regions swapped out will be present but only the occupied region slots but not the empty slots that were present before assigning.
While swapping the process once again into the main memory, the Kernel referring to the Process Memory Map, it assigns the main memory accordingly taking care of the empty slots in the regions.
9. What do you mean by u-area (user area) or u-block?
This contains the private data that is manipulated only by the Kernel. This is local to the Process, i.e. each process is allocated a u-area.
10. What are the entities that are swapped out of the main memory while swapping the process out of the main memory?
All memory space occupied by the process, process’s u-area, and Kernel stack are swapped out, theoretically.
Practically, if the process’s u-area contains the Address Translation Tables for the process then Kernel implementations do not swap the u-area.
11. What is Fork swap?
fork() is a system call to create a child process. When the parent process calls fork() system call, the child process is created and if there is short of memory then the child process is sent to the read-to-run state in the swap device, and return to the user state without swapping the parent process. When the memory will be available the child process will be swapped into the main memory.
12. What is Expansion swap?
At the time when any process requires more memory than it is currently allocated, the Kernel performs Expansion swap. To do this Kernel reserves enough space in the swap device. Then the address translation mapping is adjusted for the new virtual address space but the physical memory is not allocated. At last Kernel swaps the process into the assigned space in the swap device.  Later when the Kernel swaps the process into the main memory this assigns memory according to the new address translation mapping.
13. How the Swapper works?
The swapper is the only process that swaps the processes. The Swapper operates only in the Kernel mode and it does not uses System calls instead it uses internal Kernel functions for swapping. It is the archetype of all kernel process.
14. What are the processes that are not bothered by the swapper? Give Reason.
 Zombie process: They do not take any up physical memory.
 Processes locked in memories that are updating the region of the process.
 Kernel swaps only the sleeping processes rather than the ‘ready-to-run’ processes, as they have the higher probability of being scheduled than the Sleeping processes.
15. What are the requirements for a swapper to work?
The swapper works on the highest scheduling priority. Firstly it will look for any sleeping process, if not found then it will look for the ready-to-run process for swapping. But the major requirement for the swapper to work the ready-to-run process must be core-resident for at least 2 seconds before swapping out. And for swapping in the process must have been resided in the swap device for at least 2 seconds. If the requirement is not satisfied then the swapper will go into the wait state on that event and it is awaken once in a second by the Kernel.
16. What are the criteria for choosing a process for swapping into memory from the swap device?
The resident time of the processes in the swap device, the priority of the processes and the amount of time the processes had been swapped out.
17. What are the criteria for choosing a process for swapping out of the memory to the swap device?
 The process’s memory resident time,
 Priority of the process and
 The nice value.
18. What do you mean by nice value?
Nice value is the value that controls {increments or decrements} the priority of the process. This value that is returned by the nice () system call. The equation for using nice value is:
Priority = (“recent CPU usage”/constant) + (base- priority) + (nice value)
Only the administrator can supply the nice value. The nice () system call works for the running process only. Nice value of one process cannot affect the nice value of the other process.
19. What are conditions on which deadlock can occur while swapping the processes?
 All processes in the main memory are asleep.
 All ‘ready-to-run’ processes are swapped out.
 There is no space in the swap device for the new incoming process that are swapped out of the main memory.
 There is no space in the main memory for the new incoming process.
20. What are conditions for a machine to support Demand Paging?
 Memory architecture must based on Pages,
 The machine must support the ‘restartable’ instructions.
21. What is ‘the principle of locality’?
It’s the nature of the processes that they refer only to the small subset of the total data space of the process. i.e. the process frequently calls the same subroutines or executes the loop instructions.
22. What is the working set of a process?
The set of pages that are referred by the process in the last ‘n’, references, where ‘n’ is called the window of the working set of the process.
23. What is the window of the working set of a process?
The window of the working set of a process is the total number in which the process had referred the set of pages in the working set of the process.
24. What is called a page fault?
Page fault is referred to the situation when the process addresses a page in the working set of the process but the process fails to locate the page in the working set. And on a page fault the kernel updates the working set by reading the page from the secondary device.
25. What are data structures that are used for Demand Paging?
Kernel contains 4 data structures for Demand paging. They are,
 Page table entries,
 Disk block descriptors,
 Page frame data table (pfdata),
 Swap-use table.
26. What are the bits that support the demand paging?
Valid, Reference, Modify, Copy on write, Age. These bits are the part of the page table entry, which includes physical address of the page and protection bits.
Page address
Age Copy on write Modify Reference Valid Protection
27. How the Kernel handles the fork() system call in traditional Unix and in the System V Unix, while swapping?
Kernel in traditional Unix, makes the duplicate copy of the parent’s address space and attaches it to the child’s process, while swapping. Kernel in System V Unix, manipulates the region tables, page table, and pfdata table entries, by incrementing the reference count of the region table of shared regions.
28. Difference between the fork() and vfork() system call?
During the fork() system call the Kernel makes a copy of the parent process’s address space and attaches it to the child process.
But the vfork() system call do not makes any copy of the parent’s address space, so it is faster than the fork() system call. The child process as a result of the vfork() system call executes exec() system call. The child process from vfork() system call executes in the parent’s address space (this can overwrite the parent’s data and stack ) which suspends the parent process until the child process exits.
29. What is BSS(Block Started by Symbol)?
A data representation at the machine level, that has initial values when a program starts and tells about how much space the kernel allocates for the un-initialized data. Kernel initializes it to zero at run-time.
30. What is Page-Stealer process?
This is the Kernel process that makes rooms for the incoming pages, by swapping the memory pages that are not the part of the working set of a process. Page-Stealer is created by the Kernel at the system initialization and invokes it throughout the lifetime of the system. Kernel locks a region when a process faults on a page in the region, so that page stealer cannot steal the page, which is being faulted in.
31. Name two paging states for a page in memory?
The two paging states are:
 The page is aging and is not yet eligible for swapping,
 The page is eligible for swapping but not yet eligible for reassignment to other virtual address space.
32. What are the phases of swapping a page from the memory?
 Page stealer finds the page eligible for swapping and places the page number in the list of pages to be swapped.
 Kernel copies the page to a swap device when necessary and clears the valid bit in the page table entry, decrements the pfdata reference count, and places the pfdata table entry at the end of the free list if its reference count is 0.
33. What is page fault? Its types?
Page fault refers to the situation of not having a page in the main memory when any process references it.
There are two types of page fault :
 Validity fault,
 Protection fault.
34. In what way the Fault Handlers and the Interrupt handlers are different?
Fault handlers are also an interrupt handler with an exception that the interrupt handlers cannot sleep. Fault handlers sleep in the context of the process that caused the memory fault. The fault refers to the running process and no arbitrary processes are put to sleep.
35. What is validity fault?
If a process referring a page in the main memory whose valid bit is not set, it results in validity fault.
The valid bit is not set for those pages:
 that are outside the virtual address space of a process,
 that are the part of the virtual address space of the process but no physical address is assigned to it.
36. What does the swapping system do if it identifies the illegal page for swapping?
If the disk block descriptor does not contain any record of the faulted page, then this causes the attempted memory reference is invalid and the kernel sends a “Segmentation violation” signal to the offending process. This happens when the swapping system identifies any invalid memory reference.
37. What are states that the page can be in, after causing a page fault?
 On a swap device and not in memory,
 On the free page list in the main memory,
 In an executable file,
 Marked “demand zero”,
 Marked “demand fill”.
38. In what way the validity fault handler concludes?
 It sets the valid bit of the page by clearing the modify bit.
 It recalculates the process priority.
39. At what mode the fault handler executes?
At the Kernel Mode.
40. What do you mean by the protection fault?
Protection fault refers to the process accessing the pages, which do not have the access permission. A process also incur the protection fault when it attempts to write a page whose copy on write bit was set during the fork() system call.
41. How the Kernel handles the copy on write bit of a page, when the bit is set?
In situations like, where the copy on write bit of a page is set and that page is shared by more than one process, the Kernel allocates new page and copies the content to the new page and the other processes retain their references to the old page. After copying the Kernel updates the page table entry with the new page number. Then Kernel decrements the reference count of the old pfdata table entry.
In cases like, where the copy on write bit is set and no processes are sharing the page, the Kernel allows the physical page to be reused by the processes. By doing so, it clears the copy on write bit and disassociates the page from its disk copy (if one exists), because other process may share the disk copy. Then it removes the pfdata table entry from the page-queue as the new copy of the virtual page is not on the swap device. It decrements the swap-use count for the page and if count drops to 0, frees the swap space.
42. For which kind of fault the page is checked first?
The page is first checked for the validity fault, as soon as it is found that the page is invalid (valid bit is clear), the validity fault handler returns immediately, and the process incur the validity page fault. Kernel handles the validity fault and the process will incur the protection fault if any one is present.
43. In what way the protection fault handler concludes?
After finishing the execution of the fault handler, it sets the modify and protection bits and clears the copy on write bit. It recalculates the process-priority and checks for signals.
44. How the Kernel handles both the page stealer and the fault handler?
The page stealer and the fault handler thrash because of the shortage of the memory. If the sum of the working sets of all processes is greater that the physical memory then the fault handler will usually sleep because it cannot allocate pages for a process. This results in the reduction of the system throughput because Kernel spends too much time in overhead, rearranging the memory in the frantic pace.

Syntel | 18 Sept'10 | JAVA/J2EE

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( 1 Vote )
Syntel LTD (www.syntelinc.com)
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Experienced Walk-In : Java / J2EE
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Job Position : Java Developer / Project Lead
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No. of Openings : 70
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Job Location : Mumbai, Maharashtra
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Desired Experience : 3 to 8 Years (Mandatory)
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Job Description :
• 3 to 8+ Years of experience in Java / J2EE
• Technologies - Java script, Struts, Springs, Hibernate, Eclipse, Tomcat, PL/SQL, Websphere, HTML
• Good communication skills
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Please send your profile with the below mentioned details to : akshatha_kotegar (at) syntelinc (dot) com
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CCTC
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ECTC
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Total Experience
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Relevant Experience
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Notice Period
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Walk-In Date : On 18th September 2010 (Saturday)
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Venue :
Syntel LTD
5th Floor, Winchester,
Hiranandani Business Park,
Powai
LM: Next to Zenta BPO

Infosys

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( 0 Votes )
Infosys Technologies Ltd. (NASDAQ: INFY) was started in 1981 by seven people with US$ 250. Today, they are a global leader in the "next generation" of IT and consulting with revenues of over US$ 4 billion.
a
Infosys defines, designs and delivers technology-enabled business solutions that help Global 2000 companies win in a Flat World. Infosys also provides a complete range of services by leveraging their domain and business expertise and strategic alliances with leading technology providers.
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Their offerings span business and technology consulting, application services, systems integration, product engineering, custom software development, maintenance, re-engineering,independent testing and validation services, IT infrastructure services and business process outsourcing.
a
Infosys pioneered the Global Delivery Model (GDM), which emerged as a disruptive force in the industry leading to the rise of offshore outsourcing. The GDM is based on the principle of taking work to the location where the best talent is available, where it makes the best economic sense, with the least amount of acceptable risk.
a
Infosys has a global footprint with over 50 offices and development centers in India, China, Australia, the Czech Republic, Poland, the UK, Canada and Japan. Infosys and its subsidiaries have 105,453 employees as on September 30, 2009
Infosys takes pride in building strategic long-term client relationships. Over 97% of our revenues come from existing customers.
a
Vision
"To be a globally respected corporation that provides best-of-breed business solutions, leveraging technology, delivered by best-in-class people."
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Mission
"To achieve our objectives in an environment of fairness, honesty, and courtesy towards our clients, employees, vendors and society at large."

Atos Origin

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( 2 Votes )

Experiences of some students attending the selection process of Atos Origin.

written exam pattern:-
1. there are three sections (a) quantative apptitude = 30 ques.
(b) logical reasoning = 40 ques.
(c) english = 30 ques.

2. there is negative marking 1/2 (0.5) so be careful
3. there is sectional cutt off in each section. so time management is very important try to solve at least 50% question of each section.
some questions.
(a) quantative apptitude :-(30 question)
quanti questions are easy one r.s. agarwall is more then enough some questions are from percentage, profit and loss etc

e.g 1. two successive discounts are 20% 40% then its equivalent discount
2. if radius of cylinder is incresed by 30%  and height is decresed by 40% then what will % effect on volume of cylinder.
3.The total expense of a boarding house are partly fixed and partly variable with the number of boarders. The charge is Rs.70 per head when there are 25 boarders and Rs.60 when there are 50 boarders. Find the charge per head when there are 100 boarders.
a) 65
b) 55
c) 50
d) 45
soln.
a = fixed cost and
k = variable cost and n = number of boarders
total cost when 25 boarders c = 25*70 = 1750 i.e. 1750 = a + 25k
total cost when 50 boarders c = 50*60 = 3000 i.e. 3000 = a + 50k
solving above 2 eqns, 3000-1750 = 25k i.e. 1250 = 25k i.e. k = 50
therefore, substituting this value of k in either of above 2 eqns we get
a = 500 (a = 3000-50*50 = 500 or a = 1750 - 25*50 = 500)
so total cost when 100 boarders = c = a + 100k = 500 + 100*50 = 5500
so cost per head = 5500/100 = 55

4.Amal bought 5 pens, 7 pencils and 4 erasers. Rajan bought 6 pens, 8 erasers and 14 pencils for an amount which was half more than what Amal had paid. What % of the total amount paid by Amal was paid for pens?
a) 37.5%
b) 62.5%
c) 50%
d) None of these
soln.
Let, 5 pens + 7 pencils + 4  erasers = x  rupees
so 10 pens  + 14 pencils + 8 erasers = 2*x rupees
also mentioned, 6 pens + 14 pencils + 8 erarsers = 1.5*x rupees
so (10-6) = 4 pens = (2-1.5)x rupees
so 4 pens = 0.5x rupees => 8 pens = x rupees
so 5 pens = 5x/8 rupees  = 5/8 of total (note x rupees is total amt paid by
amal) i.e 5/8 = 500/8% = 62.5% is the answer

(5) 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?
a) 10 b) 20 c) 30.45 c) 15
soln. of 5.
2x+3y+4z=15
3x+2y+z=10
adding
5x+5y+5z=25
x+y+z=5 that is for 1 orange ,1 bannana and 1 apple requires 5Rs.
so for 3 orange ,3 bannana and 3 apple requires 15Rs.
i.e. 3x+3y+3z=15

(6) age of mohan's sister is thrice of mohan's age then what will be sister's age if mohan's age is 4 year at present. some questions are also from data interpreation. i can't remember other questions but these question certainly give you some ideas. about question level

(b  LOGICAL REASONING :-(40 question.)
data sufficiency about 4 ques., statement and conclusion about 4 ques, 4 puzzles about 16 question ,number series 4 question data interpreation 4 ques.,.......... i can't remember
some questions are:-
from data sufficiency
(1) a,b and c are three cities in straight then wht will be distance between a and b
(a) if distance between a and c is 60 k.m.
(b) ratio of distance between a and b and b and c is 2:5

(2)                  \A
\
\
x  \ y
-------------  -\--------------
B                      \             C
\
\
\D
is line AD is perpendicular to line BC
(a) if x=y
(b) AB=DC
other question i can't remember
from statement conclusion

(3) there is a notice board on the outside of an office on the notice board a statement is. read the notice board before enter into the room. then
conclusion 1. people are litrate
conclusion 2. blind people cannot enter into the office

(4) there was huge rain but traffic are not jam in town
conclusion 1.in rainy season traffic always jam
conclusion 2.
from puzzles

(5) there are 5 cricket ground eden garden, warson, lords, dambula, sidni and 5 countries england, south africa, srilanka , india,australia piches are flat, slow, spin, fast .................
can't remember..................

(6) there are 6 doctors p,q,r,s,t,u,v they pratice in a hospital monday is close day i doctor can visit the hospital every day 1 hour between 9 a.m. to 1 p.m. , 1 p.m. to 2 p.m. is lunch and 2          p.m. 5 p.m.
saturday is half day so each doctor do their duty for 1/2 hours
r alway do his duty after launch
p always be the first doctor every day who do his duty
q always be the last doctor every day who do his duty
r is followed by w
I can't remember exactly waht is but this puzzle is easy one i solved it in exam but in cricket puzzle problem i faced some difficulties..

(7) six persons A,B,C,D,E and F are sitting in two rows, three in each E  is not at the end of any row
D is second to the left of F
C, the neighbour of E , is sitting diagonally opposite D
B is the neighbour of F

(1) which of the following are sitting diagonally opposite to each other
(a) F and C     (b) D and A      (c) A and C   (d)  A and F   (e) A and B

(2) who is facing B
(a) A           (b) C            (c) D         (d) E          (e) F

(3) which of the folllowing are in the same row
(a) A and E     (b) E and D      (c) C and B   (d) A and B    (e) C and E

(4) which of the following are in the same row
(a) FBC         (b) CEB          (c) DBF       (d) AEF        (e) ABF

(5) after interchanging seat with F, who will be the neighbour of D in the new position
(a) C and A     (b) E and B      (c) only B    (d) only A     (e) only C  
soln. (1) d (2) d (3) a (4) c (5) a

8) mohan is taller then ram
mohan is taller then sohan
then what can be say
(a) ram is taller then sohan
(b) sohan is taller then ram
(c) can't tell
soln. c         

ENGLISH SECTION :---(30 question)
4 ques. like this i.e find out error in the following sentence
one of the men has(a)/to teach them properly(b)/because he is(c)/the teacher in this school(d)/no error(e)
ans- (d) because before profession a is not used so error in (d) means ' a teacher in this school ' is correct
3 ques. antonyms(easy one)
4 ques. word meaning analogy ( difficult one i can't solve any one)
4 ques. from passage ( average)
4 ques. from preposition

 

Selection procedure:
1> Aptitude Test
2> Essay Writing
3> Technical as well as H.R Interview.
a
Aptitude test
Time management is important, If there is sectional cut-off, please take judgement of lower cutoff, I did same thing, I did not attempt all question but I had attempted only selected question, because there was negative marking, don’t waste your time in attempting extra question, when u think u have answered enough question to clear that section, immediately jump to another question, then if u get time then come back for that section, I kept my mind cool I got enough to clear test but the people who tried for maximum questions or selected random answers they failed to make it. so do with cool mind”
100 Questions in 75 minutes and then 15 minutes of Essay. First they said there is negative marking of ‘-1′, but after some time they reduced the criteria they said negative marking of -0.5, but they had kept sectional cutt off.
Apti marks distubation was like 45 (Logical Reasoning) + 30 (Quantative Apti) + 25 (Verbal English)
a
Section 1: Logical reasoning
This section consists of all logical puzzles, no need of any kind of calculatoin
here u need to see book of ‘A MODERN APPROACH TO VERBAL & NON VERBAL REASONING’
Prepare following chapters from this book,
a
CHAPTER 6. PUZZLES-
Following example was there as it is in book, in Apti
‘Six persons A, B, C,D,E ande F are sitting in two rowz, three in each.
E is not at end of any row.
D is second to the left of F
C, the neighbour of E, is sitting diagonally opposite to D.
B is the neighbour of F.
answer following questions.
!. Which of the following are sitting digonally opposite to D…?
2. Who is facing B..?
3. Which of the following are in same row ?
4. which of the following are in one of two rowz ?
5. After interchanging seat with E, who will bethe neighbours of D in the new position ?
CHAPTER 2. in logical part- Statement and Arguments
Here u must prepare chapter like statements and arguments, assertion and reasoning, etc. Do it well from RS Agarwal.
example
1 >They will give u One statement. Below that there will be two statements I) & II ), as a reason.
select option a) If only stmt I) is strong reason for given statement.
b) If only statement II) is strong reason for given statement.
c) If I) & II) both are strong reason for given statement.
d) neither I) nor II) is a reason for given statement.etc.
Prepare these topic, surely there will be 5-10 questions on this topic.
a
SECTION 2: Quant Apti
refer R.S Agarwal Quant Aptitude
refer forrwing chapters
1> Train Problems
2> Boat and streams.
3> Time and distance
4> Time and work.
5> Percentage
6> ration and proportion
7> Clock
30 questiona are there total, do it very carefully. No need to attempt all question, keep eyes on your watch, do selected question first
a
SECTION 3: ENGLISH (VERY TOUGH)
here u need a bit of luck u must be very good in English, people who have given GRE or equivalent exams this is easy for them. I had not prepared for such exams so it was tough for me. There were two big paras and question were asked from that plus some synonyms and Antonyms. Try to prepare.
a
ESSAY Writing : Topic ‘Effectiveness of Technology in Medical services’
a
INTERVIEW : (TECHNICAL AND HR)
Please gather maximum knowledge from net about the company u are going for, like executive leaders in company, turnover, service areas, etc. Interview was very good experience, Panel was very friendly first they introduced themselves, then interview started
a
Question were like follows
1. Tell me something about u r self..
2. Questions from resume specially from educational background,
3. Which was the subject u hate most - I said Maths, I explained the reason, Then He agreed with me
4. which subject u love - I said Java,
5. Then they asked some questions from DBMs,
(please brush up your knowledge before going for Interview specially, C, C++, DBMS, OS, SS, Data Structure, S/W Engineering like Testing Tech, S/w Models, They can shoot any questions from that)
Otherwise prepare any one subject very well, they can ask about your favorite subject, u must be well prepared about that subject,
6. Then they asked about my career interest,
7. Then they asked if I had any questions for them.. (Please ask some sensible question)
8. they were looking very happy with me, And I walked out with enought confidence, after 3-4 hours they announced names


how to know if there are expensive sql statements running?what will you do then to improve the response time?
how to check if your r/3 system is 32bit or 64bit?
how to check if your R3 system is unicode or non-unicode?
How many types of organization data?
what is data consistency?
What is the difference between normal report program and module pool program?
How many windows can be maintained under one page?
Imagine that ten years from now a colleague is describing you to a new employee. What will s/he say
what are the document needed to create a test case?How u tell it is test case?
What is Thread ?(VC++)What is the difference between Cmutex and Csemaphone?
What?s the difference between Response.Write() andResponse.Output.Write()?
what is Initialization Purpose?
Events in Reports?
what the Recording Purpose?

 

Java Packages and interfaces

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Packages and interface
a
1) What are packages ? what is use of packages ?
Ans :The package statement defines a name space in which classes are stored.If you omit the package, the classes are put into the default package.
Signature... package pkg;
Use: * It specifies to which package the classes defined in a file belongs to. * Package is both naming and a visibility control mechanism.
2) What is difference between importing "java.applet.Applet" and "java.applet.*;" ?
Ans :"java.applet.Applet" will import only the class Applet from the package java.applet
Where as "java.applet.*" will import all the classes from java.applet package.
3) What do you understand by package access specifier?
Ans : public: Anything declared as public can be accessed from anywhere
private: Anything declared in the private can’t be seen outside of its class.
default: It is visible to subclasses as well as to other classes in the same package.
4) What is interface? What is use of interface?
Ans : It is similar to class which may contain method’s signature only but not bodies.
Methods declared in interface are abstract methods. We can implement many interfaces on a class which support the multiple inheritance.
5) Is it is necessary to implement all methods in an interface?
Ans : Yes. All the methods have to be implemented.
6) Which is the default access modifier for an interface method?
Ans : public.
7) Can we define a variable in an interface ?and what type it should be ?
Ans : Yes we can define a variable in an interface. They are implicitly final and static.
8) What is difference between interface and an abstract class?
Ans : All the methods declared inside an Interface are abstract. Where as abstract class must have at least one abstract method and others may be concrete or abstract.
In Interface we need not use the keyword abstract for the methods.
9) By default, all program import the java.lang package.
True/False
Ans : True
10) Java compiler stores the .class files in the path specified in CLASSPATH
environmental variable.
True/False
Ans : False
11) User-defined package can also be imported just like the standard packages.
True/False
Ans : True
12) When a program does not want to handle exception, the ______class is used.
Ans : Throws
13) The main subclass of the Exception class is _______ class.
Ans : RuntimeException
14) Only subclasses of ______class may be caught or thrown.
Ans : Throwable
15) Any user-defined exception class is a subclass of the _____ class.
Ans : Exception
16) The catch clause of the user-defined exception class should ______ its
Base class catch clause.
Ans : Exception
17) A _______ is used to separate the hierarchy of the class while declaring an
Import statement.
Ans : Package
18) All standard classes of Java are included within a package called _____.
Ans : java.lang
19) All the classes in a package can be simultaneously imported using ____.
Ans : *
20) Can you define a variable inside an Interface. If no, why? If yes, how?
Ans.: YES. final and static
21) How many concrete classes can you have inside an interface?
Ans.: None
22) Can you extend an interface?
Ans.: Yes
23) Is it necessary to implement all the methods of an interface while implementing the interface?
Ans.: No
24) If you do not implement all the methods of an interface while implementing , what specifier should you use for the class ?
Ans.: abstract
25) How do you achieve multiple inheritance in Java?
Ans: Using interfaces.
26) How to declare an interface example?
Ans : access class classname implements interface.
27) Can you achieve multiple interface through interface?
a)True
b) false
Ans : a.
28) Can variables be declared in an interface ? If so, what are the modifiers?
Ans : Yes. final and static are the modifiers can be declared in an interface.
29) What are the possible access modifiers when implementing interface methods?
Ans : public.
30) Can anonymous classes be implemented an interface?
Ans : Yes.
31) Interfaces can’t be extended.
a)True
b)False
Ans : b.
32) Name interfaces without a method?
Ans : Serializable, Cloneble & Remote.
33) Is it possible to use few methods of an interface in a class ? If so, how?
Ans : Yes. Declare the class as abstract.

Bajaj Capital | 14-21 Sept'10 | D2K Developer

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( 1 Vote )
Bajaj Capital Limited
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About Bajaj Capital
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Experienced Walk-In : D2K Developer
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Job Position : Software Developer
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No. of Openings : 2
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Job Location : Delhi, NCR
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Desired Experience : 1 to 5 Years (Mandatory)
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Job Description :
1. He/She should have good knowledge in Oracle Forms 6i and Reports 6i. (Both mandatory).
2. He/She should have knowledge in writing Functions, Procedures, Views, Triggers in Oracle (PL/SQL Programming).
3. He/She should have at least 1 Year experience as a Software Developer in D2K (Forms 6i & Reports 6i).
4. Knowledge in .NET will be added advantage
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Candidate Profile : Candidates with Minimum 1 year experience may apply
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Walk-In Date : On 14th-18th, 20th, 21st September 2010 | 11 AM - 5 PM
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Venue :
BAJAJ CAPITAL LTD.
97, Bajaj House,
5th Floor, Nehru Place,
New Delhi - 110019

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